String.To Chars queston

[EdzUpParticipant]

MX1 had String.ToChar and String.ToChars to convert a string to a char array, MX2 has a C string thing in the String class but it has a Void Ptr and I can’t see any info on Void Ptr I’ve tried casting to no avail.

 

Anyone have any idea how to convert a string to a array of chars?

 

Thanks in advance

[JesseParticipant]

would this work for you?:

Monkey

[crayon-5cba87f882658148518808 inline="true" ] #Import "<std>" Using std.. Function Main() Local b:Int[] = New int[5] Local a:String = "Hello World" b[0] = a[0] b[1] = a[1] b[2] = a[2] b[3] = a[3] b[4] = a[4] Print String.FromChars(b) End

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[crayon-5cba87f882658148518808 inline="true" ] #Import "<std>"   Using std..   Function Main() Local b:Int[] = New int[5] Local a:String = "Hello World" b[0] = a[0] b[1] = a[1] b[2] = a[2] b[3] = a[3] b[4] = a[4] Print String.FromChars(b) End

[/crayon]

[EdzUpParticipant]

Ah thanks Jesse didn’t know it was that easy to do

[nerobotParticipant]

@edzup How do you want to use chars array?

You can access to chars by index operator [ ], but it return INT not CHAR.

Example:

Monkey

Local str:="Hello, world!" Local latinCount:=0 For Local i:=0 Until str.Length If (str[i] >= "A"[0] And str[i] <= "Z"[0]) Or (str[i] >= "a"[0] And str[i] <= "z"[0]) Then latinCount+=1 Next Print "latinCount: "+latinCount Print "non-latinCount: "+(str.Length-latinCount)

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Local str:="Hello, world!" Local latinCount:=0 For Local i:=0 Until str.Length If (str[i] >= "A"[0] And str[i] <= "Z"[0]) Or (str[i] >= "a"[0] And str[i] <= "z"[0]) Then latinCount+=1 Next Print "latinCount: "+latinCount Print "non-latinCount: "+(str.Length-latinCount)

[EdzUpParticipant]

I was trying to do something like this:

Monkey

Field FontString:String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" Method SetChar:Int( Pos:Int, Chr:Int ) If ( Pos >FontString.Length ) Return( -1 ) Endif FontString[ Pos ] = Chr Return( 0 ) End

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Field FontString:String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"   Method SetChar:Int( Pos:Int, Chr:Int ) If ( Pos >FontString.Length ) Return( -1 ) Endif FontString[ Pos ] = Chr Return( 0 ) End

Im getting ‘Error : Value ‘Self.FontString[Pos]’ is not assignable’ on the FontString[ Pos ] = Chr line, from the posts above I thought this was the way to use it but it doesnt seem to work the same as Monkey1 is there something im missing?

[Mark SiblyKeymaster]

Strings in monkey2 are ‘immutable’: they cannot be modified. To do what you’re trying to do you’ll need to build a new string.

[EdzUpParticipant]

ah okay thanks I will recode to use slices

[Author]

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